Question

Solution A is a strong acid
Solution B is a weak acid
Solution C is a strong alkali
(i) Which solution contains solute molecules in addition to water molecules?
(ii) Which solution will give a gelatinous white precipitate with zinc sulphate solution? The precipitate disappears when an excess of the solution is added.
(iii) Which solution could be glacial acetic acid solution?
(iv) Give example of a soln. of a weak alkali.

  • Acids Bases and Salts
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Answer

(i) Solution B — weak acid

Reason

Weak Acid is an acid which dissociates only partially in aqueous solution thereby producing a low concentration of hydrogen [H+] ions [or H3O+ ions].

For example —

CH3COOH ⇌ CH3COO– + H+ [contains molecules and ions]

(ii) Solution C — strong alkali

Reason

Alkalis react with certain salt solutions to precipitate insoluble hydroxide. Hence,

ZnSO4 + 2NaOH ⟶ Na2SO4 + Zn(OH)2 [gelatinous white precipitate]

(iii) Solution B — weak acid

Reason

Anhydrous acetic acid on cooling forms crystals of glacial acetic acid and acetic acid is a weak acid.

(iv) Ammonium hydroxide (NH4OH)

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💡 Some Related Questions

Acids Bases and Salts

The diagram represents the preparation of sodium sulphate salt from dil. H2SO4 acid and sodium hydroxide.

1. Name the apparatus ‘A’.

2. Name the substance ‘X’ placed in ‘A’ and the substance ‘Y’ placed in B.

3. State the reason for conducting the titration using the apparatus ‘A’ and ‘B’.

4. State which solution is transferred to the evaporating dish and evaporated to point of crystallization for obtaining the salt.

5. State why titration is not conducted for the preparation of copper [II] sulphate crystals by neutralization.

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