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Question

State one observation for:
1. Excess NH4OH soln. is added to Pb(NO3)2
2. NaOH soln. is added to FeCl3 soln. in excess.

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Answer

Chalky white insoluble precipitate is obtained.

Pb(NO3)2 + 2NH4OH ⟶ 2NH4NO3 + Pb(OH)2 ↓

Reddish brown insoluble precipitate is obtained.

FeCl3 + 3NaOH ⟶ 3NaCl + Fe(OH)3 ↓

💡 Some Related Questions

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Action of Ammonium Hydroxide – on solutions of salts

Magnesium chloride MgCl2 + NH4OH ⟶ ____ + ____ ↓
Iron [II] sulphate FeSO4 + NH4OH ⟶ ____ + ____ ↓
Iron [III] chloride FeCl3 + NH4OH ⟶ ____ + ____ ↓
Copper [II] sulphate CuSO4 + NH4OH ⟶ ____ + ____ ↓ [Cu(OH)2 + (NH4)2SO4 + NH4OH [in excess] ⟶ ____ + ____]
Zinc sulphate ZnSO4 + NH4OH ⟶ ____ + ____ ↓ [Zn(OH)2 +(NH4)2SO4 + NH4OH [in excess] ⟶ ____ + ____]
Lead nitrate Pb(NO3)2 + NH4OH ⟶ ____ + ____↓

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