Question

State the volume occupied by 40 g of a hydrocarbon – CH4 at s.t.p. if it’s V.D. is 8.

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Answer

Vapour density of hydrocarbon = 8

∴ Molecular weight = 2 × Vapour density

= 2 × 8 = 16 g

16 g of hydrocarbon at s.t.p. occupy 22.4 lit

∴ 40 g of hydrocarbon will occupy = 22.4\over16 × 40

= 56 lit

Hence, volume occupied by 40 g of a hydrocarbon (CH4) at s.t.p. is 56 lit.

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