Flash Education

Question

Study the extract of the Periodic Table given below and answer the questions. Give the alphabet corresponding to the element in question. Do not repeat an element. State which element :
A
CDE
BGF

(i) Forms an electrovalent compound with G.
(ii) Is non-metallic and has a valency of 2?
(iii) Is an inert gas?
(iv) State the ion of which element will migrate towards the cathode during electrolysis.

WhatsApp

Answer

(i) B forms an electrovalent compound with G.

(ii) E is non-metallic and has a valency of 2 as it belongs to group 16.

(iii) F is an inert gas as it belongs to the zero group.

(iv) A has positive ions which migrate towards cathode.

💡 Some Related Questions

Flash Education Question and Answer Icon

With reference to group 1 [IA] of the periodic table – fill in the blanks with the correct word:
The elements are …………… [light/heavy] …………… [metals/non metals] since their atomic size is …………… [large/small]. The energy binding the atoms is …………… [high/low] and hence the elements have …………… [high/low] melting points. The melting points of the elements …………… [increases/decreases] down the subgroup. The electropositive character …………… [increases/decreases] down the subgroup and the elements are strong …………… [reducing/oxidizing] agents. The element with electronic configuration 2, 8, 1 will have …………… [higher/lower] electron affinity and …………… [smaller/larger] atomic size than the element with electronic configuration 2, 1.

Open Answer »
Flash Education Question and Answer Icon

In period 2, element ‘A’ is to the right of element ‘B’
(a) The element ‘A’ would probably have a …………… [smaller/larger] atomic size than ‘B’.
(b) The element ‘B’ would probably have …………… [lower/higher] ionization potential than ‘A’.
(c) The element ‘A’ would have …………… [lesser/higher] electron affinity than ‘B’.
(d) Nuclear charge of element ‘B’ would be …………… [less/more] than element ‘A’.
(e) If an element ‘C’ had a low electronegativity and ionization potential it would have more tendency to …………… [gain/lose] electrons.

Open Answer »
Close Menu