Density (ρ) = 1000 kg m -3
height (h) = 6 cm = 0.06 m
g = 10 m s-2
(a) Pressure (P) = h × ρ × g
= 0.06 × 1000 × 10
= 600 Pa
(b) Area = 300 cm 2 = 3 × 10-2 m 2
Thrust (F) = 600 × 3 × 10-2 = 18 N
Hence, thrust = 18 N
Question
The area of base of a cylindrical vessel is 300 cm 2. Water (density = 1000 kg m -3) is poured into it up to a depth of 6 cm. Calculate (a) the pressure and (b) the thrust of water on the base. (g = 10 m s-2).
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