Atomic number of Al = Number of electrons = 13
Number of electrons in Al3+ = 13 – 3 = 10
Atomic number of chlorine = Number of electrons = 1 7
Number of electrons in CI– = 17 + 1 = 18
Atomic number of Al = Number of electrons = 13
Number of electrons in Al3+ = 13 – 3 = 10
Atomic number of chlorine = Number of electrons = 1 7
Number of electrons in CI– = 17 + 1 = 18