12 years 3 months = 12 × 365 + 3 × 30 = 4470 days
= 4470 × 24 × 60 × 60 s
= 386208000 s
12 years 3 months = 12 × 365 + 3 × 30 = 4470 days
= 4470 × 24 × 60 × 60 s
= 386208000 s
Q1. What does the graph between point B and C indicate about the motion of Boojho? Q2. Is the motion between 0 to 4 minutes uniform or non-uniform? Q3. What is his speed between 8 and 12 minutes of his journey?
| Distance (m) | 0 | 4 | ? | 12 | ? | 20 |
| Time (s) | 0 | 2 | 4 | ? | 8 | 10 |