Since average atomic mass
= 16 x X + 18 x (100 – X )/100
16.2 = 16X + 1800 – 18X/100
1620 = – 2X + 1800
2X = 1800 – 1620
X = 180/2 = 90
When 90% is the X-16 sample so for X-18 sample % = 100-90=10%
Question
The average atomic mass of a sample of an element X is 16.2 u. What are the percentages of isotopes 𝑋8 16 and 𝑋8 18 in the sample?
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