Given,
Density of ice = 0.92 g cm-3
Density of sea water = 1.025 g cm-3
Let the total volume of the iceberg be V cm3
The volume of the iceberg above sea water = 800 cm3
Volume of iceberg immersed in seawater = (V – 800) cm3
By the principle of floatation,
{Volume\ of\ immersed\ part\over Total\ volume} = {Density\ of\ ice\over Density\ of\ water}⇒ {V-800\over V} = {0.92\over 1.025}
⇒ 1.025 V – 820 = 0.92 V
⇒ 1.025 V – 0.92 V = 820
⇒ 0.105 V = 820
⇒ V = 820\over 0.105 = 7809.52 cm3
Hence, Total volume of iceberg = 7809.52 cm3