Question

The density of ice is 0.92 g cm-3 and that of sea water is 1.025 g cm-3. Find the total volume of an iceberg which floats with it’s volume 800 cm3 above water.

  • Category: Upthrust in Fluids Archimedes' Principle and Floatation Class 9 ICSE
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Answer

Given,

Density of ice = 0.92 g cm-3

Density of sea water = 1.025 g cm-3

Let the total volume of the iceberg be V cm3

The volume of the iceberg above sea water = 800 cm3

Volume of iceberg immersed in seawater = (V – 800) cm3

By the principle of floatation,

{Volume\ of\ immersed\ part\over Total\ volume} = {Density\ of\ ice\over Density\ of\ water}

⇒ {V-800\over V} = {0.92\over 1.025}

⇒ 1.025 V – 820 = 0.92 V

⇒ 1.025 V – 0.92 V = 820

⇒ 0.105 V = 820

⇒ V = 820\over 0.105 = 7809.52 cm3

Hence, Total volume of iceberg = 7809.52 cm3

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