Given,

Density of ice = 0.92 g cm^{-3}

Density of sea water = 1.025 g cm^{-3}

Let the total volume of the iceberg be V cm^{3}

The volume of the iceberg above sea water = 800 cm^{3}

Volume of iceberg immersed in seawater = (V – 800) cm^{3}

By the principle of floatation,

{Volume\ of\ immersed\ part\over Total\ volume} = {Density\ of\ ice\over Density\ of\ water}⇒ {V-800\over V} = {0.92\over 1.025}

⇒ 1.025 V – 820 = 0.92 V

⇒ 1.025 V – 0.92 V = 820

⇒ 0.105 V = 820

⇒ V = 820\over 0.105 = 7809.52 cm^{3}

Hence, **Total volume of iceberg = 7809.52 cm ^{3}**