| 4NH3 | + | 5O2 | → | 2NO | 6H2O |
| 4 vol | : | 5 vol | 4 vol |
To calculate the volume of oxygen required :
| NH3 | : | O2 |
| 4 | : | 5 |
| 100 | : | x |
⇒ x = 5\over 4 × 100 = 125 cm3
Hence, volume of oxygen required = 125 cm3
| 4NH3 | + | 5O2 | → | 2NO | 6H2O |
| 4 vol | : | 5 vol | 4 vol |
To calculate the volume of oxygen required :
| NH3 | : | O2 |
| 4 | : | 5 |
| 100 | : | x |
⇒ x = 5\over 4 × 100 = 125 cm3
Hence, volume of oxygen required = 125 cm3