(i)
2NaHCO3 → Na2CO3 + H2O + CO2
168 g 106 g
106 g of Na2CO3 is obtained from 168 g of NaHCO3
∴ 21.2 g. of Na2CO3 is obtained from 168\over 106 × 21.2 = 33.6 g of NaHCO3
(ii)
NaCl + NH3 + CO2 + H2O → NaHCO3 + NH4Cl
. 22.4 lit 84 g
84 g of NaHCO3 is obtained from 22.4 lit of CO2
∴ 33.6 g. of NaHCO3 is obtained from 22.4\over 84 × 33.6
= 8.96 lit.
Hence, 8.96 lit of CO2 is required.