Area of the field = 20 m × 15 m = 300 sqm.
Area of the land for 4 pillars = 4 × (4)2 Sqm. = 64 sqm.
∴ Remaining part of the land = (300-64) Sqm. = 236 sqm.
The volume of ear’ removed =4 × (4)3 cum. = 256 cum.
Let’s increase the height of the remaining field x m.
∴ 236 × x = 256
x =\frac{256}{236}=\frac{64}{59}=1 \frac{5}{59} m.