Question

The length and breadth of cuboidal water land in neighbouring villages are 18 m and 11 m respectively. In this water land, water is being irrigated from a nearby pond with a pump. If the pump can irrigate 39,600 lit. water per hour then for how much time is required to raise the height of the water level by 3.5 dcm of the water land – let us write by calculating it. [ 1 lit. -1 cubic dcm.]

January 1, 2024

Answer

The pump will run $=\frac{180 × 110 × 3.5}{39600}$ hr.

$=\frac{180 × 110 × 35}{39600 × 10}$ × 60 min

= 35 × 3 = 105 min

= 1 hr 45 min.

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