magnification (m) = –image\ distance\ (v)\over object\ distance\ (u)
Hence, we get,
-3 = –v\over u
v = 3u
Hence, v = 3u
magnification (m) = –image\ distance\ (v)\over object\ distance\ (u)
Hence, we get,
-3 = –v\over u
v = 3u
Hence, v = 3u
Was this answer helpful?