3CuO + 2NH3 ⟶ 3Cu + 3H2O + N2
240 g 44.8 lit
240 g of CuO is reduced by 44.8 lit of NH3
∴ 120 g of CuO is reduced by 44.8\over 240 × 120 = 22.4 lit.
Hence, 22.4 lit of NH3 is required
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