q1 + q2 = 7µ —- (i)
F = {1\over 4 \pi\varepsilon_0}{q_1q_2\over r^2} {1\over 4 \pi\varepsilon_0}{q_1q_2\over r^2}=1or, q1 q2 = (4πεo)(0.30)2
or, q1 q2 = 10-11 —- (ii)
(q1 – q2)2 = (q1 + q2)2 – 4q1 q2
= (7µ)2 – 4×10-11
= 49 × 10-12 – 40×10-12
or, (q1 – q2)2 = 9 × 10-12
or, q1 – q2 = 3 × 10-6 —- (iii)
Solving (i) and (iii), we get
q1 = 5 × 10-6 C = 5µ and q2 = 7µ – 5µ = 2 µC