Time interval (t) = 5 s

Speed (V) = 330 m s^{-1}

distance (d) = ?

V = Distance\over Time

Substituting the values, we get,

330 = d\over 5

⇒ d = 330 × 5 = 1650 m

Therefore, **the distance of flash from the observer = 1650 s.**

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## Question

# The time interval between a lightning flash and the first sound of thunder is 5 s. If the speed of sound in air is 330 m s-1 , find the distance of flash from the observer.

## Answer

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Time interval (t) = 5 s

Speed (V) = 330 m s^{-1}

distance (d) = ?

V = Distance\over Time

Substituting the values, we get,

330 = d\over 5

⇒ d = 330 × 5 = 1650 m

Therefore, **the distance of flash from the observer = 1650 s.**

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