There were 800 lit 725 lit and 575 lit kerosene oil in three kerosine oil drums the house. The oil of these three drums is poured into a cuboidal pot and for this, the depth of oil in drums becomes 7 dcms. If the ratio of the length and breadth of the cuboidal pot is 4 : 3, then let us write by calculating the length and breadth of the pot. If the depth of the cuboidal pot would be 5 dcm, then let us calculate whether 162 lit oil can be kept or not in that pot

Let the length & the breadth of the rectangular tank are 4x dcm & 3x dc respectively.

Total volume of soil = (800+725+575) litre.

\therefore Volume of the tank = (4x × 3x × 7) cu.dcm.

According to the problem,

4x × 3x × 7 = 2100

or, 84x² = 2100

∴ x² =\frac{2100}{84}= 25

∴ x = \sqrt{25} = 5

Length & breadth of the tank = (4 × 5) dcm and (3 × 5) dcm = 20 dcm & 15 dcm.

2nd part :

If the height tank = 5 dcm.

∴ Its volume will be = (20 × 15 × 5) cu.dcm. = 1500 cu.dcm = 1500 litre.

But total volume of oil = 2100 litre.

∴ It is not possible to keep 1620 litre oil in the 2nd tank.