Flash Education

Question

To make a saturated solution, 36 g of sodium chloride is dissolved in 100 g of water at 293 K. Find its concentration at this temperature.

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Answer

Mass of solute (sodium chloride) = 36 g (Given)

Mass of solvent (water) = 100 g (Given)

Then, mass of solution = Mass of solute + Mass of solvent

= (36 + 100) g

= 136 g

Therefore, concentration (mass by mass percentage) of the solution

= {๐‘€๐‘Ž๐‘ ๐‘ \ ๐‘œ๐‘“\ ๐‘ ๐‘œ๐‘™๐‘ข๐‘ก๐‘’ \over ๐‘€๐‘Ž๐‘ s\ ๐‘œ๐‘“\ ๐‘ ๐‘œ๐‘™๐‘ฃ๐‘’๐‘›๐‘ก} ร— 100 %

={36\over136} ร— 100 %

= 26.4 %

๐Ÿ’ก Some Related Questions

Pragya tested the solubility of three different substances at different temperatures and collected the data as given below (results are given in the following table, as grams of substance dissolved in 100 grams of water to form a saturated solution).
Substance dissolvedTemperature in K
283293313333353
Potassium nitrate213262106167
Sodium chloride3636363737
Potassium chloride3535404654
Ammonium chloride2437415566

(a)What mass of potassium nitrate would be needed to produce a saturated solution of potassium nitrate in 50 grams of water at 313 K? (b)Pragya makes a saturated solution of potassium chloride in water at 353 K and leaves the solution to cool at room temperature. What would she observe as the solution cools? Explain. (c) Find the solubility of each salt at 293 K. Which salt has the highest solubility at this temperature? (d)What is the effect of change of temperature on the solubility of a salt?

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