Force will decrease
Reason: Force between two charges each ‘q’ in vacuum is F_o = {1\over 4 \pi\varepsilon_0}{q^2\over r^2}
On inserting a plastic sheet (a dielectric K > 1)
Then F = {1\over 4 \pi\varepsilon_0K}{q^2\over r^2} i.e F = {F_o\over K}
Force will decrease
Reason: Force between two charges each ‘q’ in vacuum is F_o = {1\over 4 \pi\varepsilon_0}{q^2\over r^2}
On inserting a plastic sheet (a dielectric K > 1)
Then F = {1\over 4 \pi\varepsilon_0K}{q^2\over r^2} i.e F = {F_o\over K}
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