Two simple pendulums A and B have lengths 1.0 m and 4.0 m respectively at a certain place. Which pendulum will make more oscillations in 1 minute? Explain your answer.

Given,

l_A = 1.0m

l_B = 4.0m

Since,

T ∝ √l

or, {T_A\over T_B}={\sqrt {l_A}\over \sqrt {l_b}}

or, {T_A\over T_B}={\sqrt {1}\over \sqrt {4}}

or, {T_A\over T_B}={1\over 4}

i.e., T₁ : T₂ = 1 : 2

∴ Time period of B is more (twice) than that of A. Hence, A will make more oscillations (twice) in a given time than B.