Molecular Weight of Silver Nitrate (AgNO3) = 108 + 14 + 48 = 170 g
Molecular Weight of Silver Chloride (AgCl) = 108 + 35.5 = 143.5 g
Balanced Chemical Equation:
AgNO3 + HCl → AgCl + HNO3
170 g 143.5 g
170 g of AgNO3 gives 143.5 g of AgCl
∴ 0.34 g of AgNO3 will give 143.5\over 170 × 0.34
= 0.287 g of AgCl
Hence, 0.287 g of silver chloride will be