(a) Time = {Distance \over Speed}
or t = {2d \over v}
or d = {vΓπ‘ \over 2} = {vΓ1 \over 2Γ10} (β΅ Time = 0.1 s) = {π£ \over 2d}
(b) The speed of sound increases with temperature. So, on a hotter day speed of sound is more.
(a) Time = {Distance \over Speed}
or t = {2d \over v}
or d = {vΓπ‘ \over 2} = {vΓ1 \over 2Γ10} (β΅ Time = 0.1 s) = {π£ \over 2d}
(b) The speed of sound increases with temperature. So, on a hotter day speed of sound is more.