(a) Time = {Distance \over Speed}
or t = {2d \over v}
or d = {v×𝑡 \over 2} = {v×1 \over 2×10} (∵ Time = 0.1 s) = {𝑣 \over 2d}
(b) The speed of sound increases with temperature. So, on a hotter day speed of sound is more.
(a) Time = {Distance \over Speed}
or t = {2d \over v}
or d = {v×𝑡 \over 2} = {v×1 \over 2×10} (∵ Time = 0.1 s) = {𝑣 \over 2d}
(b) The speed of sound increases with temperature. So, on a hotter day speed of sound is more.