[By Lussac’s law]
2C4H10 + 13O2 ⟶ 8CO2 + 10H2O
2 vol : 13 vol ⟶ 8 vol : 10 vol
To calculate the volume of oxygen
C4H10 : O2
2 : 13
90 : x
⇒ x = 13\over 2 × 90 = 585 dm3
Hence, the volume of oxygen is required is 585 dm3
[By Lussac’s law]
2C4H10 + 13O2 ⟶ 8CO2 + 10H2O
2 vol : 13 vol ⟶ 8 vol : 10 vol
To calculate the volume of oxygen
C4H10 : O2
2 : 13
90 : x
⇒ x = 13\over 2 × 90 = 585 dm3
Hence, the volume of oxygen is required is 585 dm3
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