QQuestion
85 g of water at 30°C is cooled to 5°C by adding certain mass of ice. Find the mass of ice required.
[Specific heat capacity of water = 4.2 J g−1 °C−1, Specific latent heat of fusion = 336 J g−1]
85 g of water at 30°C is cooled to 5°C by adding certain mass of ice. Find the mass of ice required.
[Specific heat capacity of water = 4.2 J g−1 °C−1, Specific latent heat of fusion = 336 J g−1]
Heat lost by water = 85 × 4.2 × (30 − 5) = 8925 J.
Let mass of ice be ‘m’ g.
Heat gained by ice = mL + mc△t
= m × 336 + m × 4.2 × 5
= 357m.
By the principle of calorimetry, 8925 = 357m.
m = \frac{8925}{357} = 25 g.
Therefore, the mass of ice required is 25 g.
More ICSE Easy level questions
(a) Why does it become pleasantly warm when the lakes start freezing? (b) Water freezes to form ice. What change would you expect in the average kinetic energy of the molecules? (c) Which will contain more heat energy 1 g of ice at 0°C or 1 g water at 0°C?
During the melting of ice at 0°C: (a) energy is released and temperature remains constant (b) energy is absorbed and temperature remains constant (c) energy is absorbed and temperature rises (d) energy is released and temperature falls
fHow much heat is required to convert 500 g of ice at 0°C to water at 0°C? The latent heat of fusion of ice is 330 J g−1.
The graph given below shows heat energy supplied against change in temperature when no energy is lost to the surrounding. The slope of this graph will give: (a) specific heat capacity (b) specific latent heat of fusion (c) specific latent heat of vaporisation (d) heat capacity
Calculate the total amount of heat energy required to melt 200 g of ice at 0°C to water at 100°C. (Specific latent heat of ice = 336 J g−1, specific heat capacity of water = 4.2 J g−1 °C−1)
(a) State the principle of calorimetry. (b) Name the material used for making a calorimeter. (c) Write one characteristic property of the material chosen for making a calorimeter.
(a) A certain amount of heat will warm 1 g of material X by 10°C and 1 g of material Y by 40°C. Which material has higher specific heat capacity? (b) Which material, X or Y, would you select to make a calorimeter? (c) The specific heat capacity of a substance remains the same when it changes its state from solid to liquid. State True or False.
30 g of ice at 0°C is used to bring down the temperature of a certain mass of water at 70°C to 20°C. Find the mass of water. Specific heat capacity of water = 4.2 J g⁻¹ °C⁻¹ and specific latent heat of ice = 336 J g⁻¹.
A metal piece of mass 5 g has thermal capacity 2.5 J K⁻¹. If the mass of the metal is tripled, then its specific heat capacity will be : (a) 7.5 J K⁻¹ (b) 2.5 J K⁻¹ (c) 1.5 J g⁻¹ K⁻¹ (d) 0.5 J g⁻¹ K⁻¹
Specific heat capacity of a substance X is 1900 J kg−1 °C−1 means: (a) Substance X absorbs 1900 J for 1°C rise in temperature (b) 1 kg of substance X absorbs 1900 J heat for 1°C rise in temperature (c) 1 kg of substance X absorbs 1900 J heat to increase the temperature (d) 1 kg of substance X absorbs 1900 J heat to cool down by 1°C
Calculate the amount of heat absorbed by 200 g of paraffin wax to melt completely at its melting point. [Specific latent heat of fusion of paraffin wax = 146 J g⁻¹]
Each of the substances given below is supplied with same amount of heat. Which one will attain the highest temperature? Substance Specific heat capacity (cal/g°C) Lead 0.031 Aluminium 0.21 Copper 0.095 Iron 0.115 (a) Aluminium (b) Copper (c) Iron (d) Lead