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ICSEClass XBiologyGenetics01 Mark2026 Hard

QQuestion

A sequence of DNA has 300 nitrogenous base pairs, of which 75 are Guanine. What is the number of Thymine in this sequence?

(a) 150

(b) 100

(c) 50

(d) 75

Exam-ready answer • 01 Mark

Answer

(d) 75

If Guanine = 75, then cytosine = 75

So, Guanine + Cytosine = 75 + 75 = 150

Remaining bases = 300 – 150 = 150

Adenine + Thymine = 150

Since, Adenine = Thymine

So, we will divide 150 equally between them.

150/2 = 75

So, Adenine = Thymine = 75

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