QQuestion
Refer to the bill below. A customer paid ₹2,000, rounded to the nearest ₹10, to clear it.
Note: A 5% discount applies to an article when 10 or more units are purchased.
| Article | Marked price | Quantity | GST |
|---|---|---|---|
| A | ₹190 | 6 | 12% |
| B | ₹50 | 12 | 18% |
Check whether the amount paid is correct. Justify your answer with working.
Exam-ready answer • 04 Mark
✓Answer
For Article A:
Total marked price = ₹190 × 6 = ₹1,140
GST = 12% of ₹1,140
⇒ GST = \frac{12}{100} × ₹1,140
⇒ GST = ₹136.80
Total for A = ₹1,140 + ₹136.80 = ₹1,276.80
For Article B:
Total marked price = ₹50 × 12 = ₹600
Since 12 units are purchased, discount = 5% of ₹600.
⇒ Discount = ₹30
Taxable value = ₹600 − ₹30 = ₹570
GST = 18% of ₹570
⇒ GST = \frac{18}{100} × ₹570
⇒ GST = ₹102.60
Total for B = ₹570 + ₹102.60 = ₹672.60
Total bill = ₹1,276.80 + ₹672.60
⇒ Total bill = ₹1,949.40
Rounded to the nearest ₹10, the bill is ₹1,950.
The customer paid ₹2,000.
Extra amount paid = ₹2,000 − ₹1,950 = ₹50
Therefore, the payment was not correct; the customer paid ₹50 extra.
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