QQuestion
Copy and complete the nuclear reaction by filling in the blanks.
{}_{92}^{235}U+{}_{0}^{1}n\longrightarrow{}_{56}^{\ldots}Ba+{}_{\ldots}^{92}Kr+3{}_{0}^{1}n✓Answer
As only neutrons are involved in the reaction, the number of protons and total nucleon number remain constant.
Initially, number of protons = 92 and number of nucleons = 235 + 1 = 236.
Let the atomic number of Kr be Z and the mass number of Ba be A.
92 = 56 + Z, so Z = 36.
236 = A + 92 + 3, so A = 141.
Therefore,
{}_{92}^{235}U+{}_{0}^{1}n\longrightarrow{}_{56}^{141}Ba+{}_{36}^{92}Kr+3{}_{0}^{1}nRelated Questions
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