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ICSEClass XMathematicsMensuration04 Mark2026 Easy

QQuestion

The given figure shows an eye-drop bottle consisting of a hemispherical part and a cylindrical part, with a conical cap. The height of the cylindrical part and the height of the conical cap are each equal to the diameter, 7 cm.

The given figure shows an eye-drop bottle consisting of a hemispherical part and a cylindrical part, with a conical cap

(a) Find the minimum height of a cylindrical box in which the bottle can be packed.

(b) Find the volume of the liquid medicine that the bottle can contain. Use π = 22/7.

Exam-ready answer • 04 Mark

Answer

Diameter = 7 cm

Therefore, radius r = 7/2 = 3.5 cm.

Height of the cylindrical part = 7 cm.

Height of the conical cap = 7 cm.

(a) From the given arrangement, the minimum height of the cylindrical box is:

7 + 7 = 14 cm

Therefore, the minimum height of the cylindrical box is 14 cm.

(b) The liquid is contained in the hemispherical and cylindrical parts.

Volume of hemisphere = \frac{2}{3}\pi \mathrm{r}^3

= \frac{2}{3}\times\frac{22}{7}\times(3.5)^3

= 89.83 cm³

Volume of cylinder = πr²h

= \frac{22}{7}\times(3.5)^2\times7

= 269.5 cm³

Total volume = 89.83 + 269.5

= 359.33 cm³

Therefore, the bottle can contain approximately 359 cm³ of liquid medicine.

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