QQuestion
Find the mean by any suitable method from the following frequency distribution table
| Class Interval | Frequency |
| 85 – 105 | 3 |
| 105 – 125 | 12 |
| 125 – 145 | 18 |
| 145 – 165 | 10 |
| 165 – 185 | 5 |
| 185 – 205 | 2 |
Exam-ready answer • 04 Mark
✓Answer
| Class Interval | mid-point (x) | Frequency (f) | fx |
| 85 – 105 | 95 | 3 | 285 |
| 105 – 125 | 115 | 12 | 1380 |
| 125 – 145 | 135 | 18 | 2430 |
| 145 – 165 | 155 | 10 | 1550 |
| 165 – 185 | 175 | 5 | 875 |
| 185 – 205 | 195 | 2 | 390 |
| Total | Σf = 50 | Σfx = 6910 |
Mean = Σfx\over Σf
= 6910\over 50\
= 138.2
The mean of the distribution is 138.2.
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