QQuestion
Ethane burns in oxygen according to the chemical equation:
2C2H6 + 7O2 → 4CO2 + 6H2O
If 80 ml of ethane is burnt in 300 ml of oxygen, find the composition of the resultant gaseous mixture when measured at room temperature. [3]
Exam-ready answer • 03 Mark
✓Answer
The resultant gaseous mixture contains 160 ml of carbon dioxide and 20 ml of unused oxygen.
By Gay-Lussac’s law, the reacting gas volumes are in the ratio:
Ethane : oxygen : carbon dioxide = 2 : 7 : 4.
Oxygen consumed:
\frac{7}{2}\times80=280\text{ ml}Oxygen remaining = 300 − 280 = 20 ml.
Carbon dioxide formed:
\frac{4}{2}\times80=160\text{ ml}All 80 ml of ethane is consumed. At room temperature, the water formed is taken as condensed liquid and is not included in the gaseous mixture.
Total gas volume = 160 + 20 = 180 ml.
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