QQuestion
‘O’ is the center of a circle and PQ is a diameter. R is a point on the circle such that PR = RQ, then the value of ∠RPQ:
(a) 30°
(b) 90°
(c) 60°
(d) 45°
✓Answer
(d) 45°
Explanation:
Since PR = RQ, triangle PRQ is isosceles, and ∠PRQ = 90° (because PQ is the diameter).
So, ∠RPQ = ∠RQP = 45°.
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