QQuestion
The height of a right circular cylinder is twice the radius of the base. If the height is 6 times of the radius, then the volume of the cylinder is 539 cubic decimeter more than the previous volume. Find the height of the cylinder.
Exam-ready answer • 04 Mark
✓Answer
Let the original radius of the base be r and the original height be h.
From the given condition:
h = 2r
The volume of a cylinder is given by:
V = π r² h
Substituting h = 2r in the volume formula:
V₁ = π r² (2r)
V₁ = 2π r³
Now, the new height is 6 times the radius, so:
h’ = 6r
The new volume is:
V₂ = π r² (6r)
V₂ = 6π r³
According to the problem, the difference in volume is 539 cubic decimeters:
V₂ – V₁ = 539
Substituting the values of V₁ and V₂:
6π r³ – 2π r³ = 539
4π r³ = 539
Substituting π ≈ \frac{22}{7} :
4 × \frac{22}{7} × r³ = 539
\frac{88}{7} × r³ = 539
Multiplying both sides by 7:
88 r³ = 3773
⇒ r³ = \frac{3773}{88}
⇒ r³ = \frac{343}{8}
⇒ r = 3.5 dm
∴ height = 2r
= 2 × 3.5
= 7 cm
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