QQuestion
The hydrocarbon formed when sodium propanoate and soda lime are heated together:
(a) Methane
(b) Ethane
(c) Ethene
(d) Propane
✓Answer
b. Ethane
Explanation:
Heating sodium propanoate with soda lime causes decarboxylation. The alkane formed has one carbon atom fewer than the original carboxylate.
\mathrm{CH_3CH_2COONa}+\mathrm{NaOH}\xrightarrow{\mathrm{CaO},\,\Delta}\mathrm{C_2H_6}+\mathrm{Na_2CO_3}Sodium propanoate has three carbon atoms; the hydrocarbon product, ethane, has two.
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