QQuestion
The diagram shows a ray of light travelling from medium A to medium B.
The refractive index of medium B with respect to medium A is:
(a) \frac{\sin 45^\circ}{\sin 30^\circ}
(b) \frac{\sin 30^\circ}{\sin 45^\circ}
(c) \frac{\sin 45^\circ}{\sin 60^\circ}
(d) \frac{\sin 60^\circ}{\sin 45^\circ}
✓Answer
(d) \frac{\sin 60^\circ}{\sin 45^\circ}
Explanation:
The angle of incidence = 60° and
the angle of refraction = 45°.
Therefore, refractive index of B with respect to A = \frac{\sin 60^\circ}{\sin 45^\circ}.
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