Let each resistor be R.

When connected in series,

Equivalent resistance = 3R

Given, Power dissipated = 10 W

Using the formula, P = \frac{V^2}{R}

⇒ 10 = \frac{V^2}{3R}

⇒ V² = 10 × 3R = 30 R

When the same resistors are connected in parallel,

Equivalent resistance = \frac{R}{3}

Power (P) = \frac{V^2}{R/3} = \frac{3V^2}{R}

Substituting V² = 30R,

P = \frac{3 \times 30R}{R} = 90 W

Hence, the power dissipated in the parallel combination is 90 W.