(c) 3
Reason — When two mirrors are kept perpendicular to each other i.e., θ = 90°,
then n = 360\over 90 = 4
n = 4, is even so the number of images is n – 1
Therefore,
n – 1
= 4 – 1
= 3
Question
The number of images formed for two mirrors kept perpendicular to each other is :(a) 1(b) 2(c) 3(d) 5
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