During upward motion, acceleration = – g and during downward motion acceleration = + g. Times of upward and downward motion is equal. Also initial and final velocities are equal to (g {T \over Z} ) .

During upward motion, acceleration = – g and during downward motion acceleration = + g. Times of upward and downward motion is equal. Also initial and final velocities are equal to (g {T \over Z} ) .

| Time in (s) | Body (A) | Body (B) | Body (C) |
| 1stSecond | 20 | 20 | 20 |
| 2ndSecond | 20 | 36 | 60 |
| 3rdSecond | 20 | 24 | 100 |
| 4thSecond | 20 | 30 | 140 |
| 5thSecond | 20 | 48 | 180 |
Observe the graph carefully and answer the following questions. (i) Which part of the graph shows the squirrel moving away from the tree? (ii) Name the point on the graph which is 6 m away from the base of the tree. (ii) Which part of the graph shows that the squirrel is not moving? (iv) Which part of the graph shows that the squirrel is returning to the tree? (v) Calculate the speed of the squirrel from the graph during its journey.