Question

Obtain a relation for the distance travelled by an object moving with a uniform acceleration in the interval between 4th and 5th seconds.

  • Motion CBSE Class 9
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Answer

Using the equation of motion s = ut + {1 \over2}at^2

Distance travelled in 5 seconds, s = u \times 5 + {1\over2}a \times 5^2

Or  s = 5u+{25\over2}a …….(1)

Similarly, distance travelled in 4 seconds,     s’ = 4u+{16\over2}a ….(2)

Distance travelled in the interval between 4th and 5th seconds

= (s – s’) = (u+{9\over2}a)m

 

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