Question

A compound has a formula = ‘H2Y’. Y denotes a non-­metal. State the following:
1. The electronic configuration of Y.
2. The valency of Y.
3. The bonding present in ‘H2Y’
4. The bonding present in the compound formed between potassium (19K39) and ‘Y’
5. The formula of the compound formed between calcium (20Ca40) and Y.

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Answer

  1. The element Y needs 2 electrons to complete it’s octet, so it will have 6 electrons in the outer most shell. Hence, will have 2, 6 as the electronic configuration. It is the electronic configuration of non-metal ‘Oxygen’.
  2. 2 is the valency of element Y as it has 6 electrons in the outer most shell and needs two electrons to complete it’s octet and attain a stable state.
  3. Covalent bond is present because each of hydrogen atom shares an electron pair with element Y such that hydrogen acquires a duplet configuration and Y an octet configuration and both become stable, hence form covalent bond.
  4. Ionic bond is present between potassium (19K39) and ‘Y’ because K is a metal and Y is a non-metal.
  5. CaY is the formula for the compound formed between calcium (20Ca40) and Y by transfer of two valence electrons. (As the electronic configuration of Y matches that of Oxygen so the actual formula will be CaO)

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Chemical Bonding

Fill in the blanks with the correct word from the brackets:
(i) The bond between two elements in group 17[VIIA] of the periodic table is likely to be ____ [ionic/covalent].
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