Solve: x + 3\over x - 3 + x - 3\over x + 3 = 21\over 2, (x ≠ -3, 3)
WBBSE
Class X
Mathematics
Quadratic Equation With One Variable
03 Mark
2025
x + 3\over x - 3 + x - 3\over x + 3 = \frac{5}{2}.
(x + 3)² + (x - 3)² \over (x + 3)(x - 3) = \frac{5}{2}.
⇒ (x + 3)² + (x - 3)² \over (x + 3)(x - 3) = \frac{5}{2}
⇒ (x² + 6x + 9) + (x² - 6x + 9) \over x² - 9 = \frac{5}{2}
⇒ 2x² + 18 \over x² - 9 = \frac{5}{2}
⇒ 2(2x² + 18) = 5(x² – 9)
⇒ 4x² + 36 = 5x² – 45
Subtract 4x² from both sides:
36 = x² – 45
⇒ x² = 36 + 45 = 81
Taking square roots, we get:
x = ± 9
Since x ≠ -3, 3, both solutions x = 9 and x = – 9 are acceptable.
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