QQuestion
The equivalent resistance of two resistors R1 and R2 connected in parallel is:
(a) \frac{\mathrm{R}_1+\mathrm{R}_2}{\mathrm{R}_1\mathrm{R}_2}
(b) \frac{\mathrm{R}_1\mathrm{R}_2}{\mathrm{R}_1+\mathrm{R}_2}
(c) \frac{\mathrm{R}_1-\mathrm{R}_2}{\mathrm{R}_1\mathrm{R}_2}
(d) \frac{\mathrm{R}_1\mathrm{R}_2}{\mathrm{R}_1-\mathrm{R}_2}
Exam-ready answer • 01 Mark
✓Answer
(b) \frac{\mathrm{R}_1\mathrm{R}_2}{\mathrm{R}_1+\mathrm{R}_2}
Explanation:
For two parallel resistors, \frac{1}{\mathrm{R}}=\frac{1}{\mathrm{R}_1}+\frac{1}{\mathrm{R}_2}.
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