ICSEClass XMathematicsArithmetic And Geometric Progression03 Mark2023 Easy

QQuestion

The 5th term and the 9th term of an Arithmetic Progression are 4 and −12 respectively. Find:

(a) the first term

(b) the common difference

(c) the sum of 16 terms of the A.P.

Exam-ready answer 03 Mark

Answer

Let the first term be a and the common difference be d.

The nth term of an A.P. is:

an = a + (n − 1)d

Given, the 5th term is 4:

⇒ a + (5 − 1)d = 4

⇒ a + 4d = 4 … (1)

Given, the 9th term is −12:

⇒ a + (9 − 1)d = −12

⇒ a + 8d = −12 … (2)

Subtracting (1) from (2):

⇒ (a + 8d) − (a + 4d) = −12 − 4

⇒ a + 8d − a − 4d = −16

⇒ 4d = −16

⇒ d = −4

Substituting d = −4 in (1):

⇒ a + 4(−4) = 4

⇒ a − 16 = 4

⇒ a = 20

(a) Therefore, the first term is 20.

(b) The common difference is −4.

(c) Sum of n terms: Sn = \frac{n}{2}[2a+(n-1)d]

⇒ S16 = \frac{16}{2}[2(20)+(16-1)(-4)]

⇒ S16 = 8[40 − 60]

⇒ S16 = 8(−20)

Therefore, S16 = −160.

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