ICSEClass XMathematicsArithmetic And Geometric Progression04 Mark2025 Moderate

QQuestion

If 1701 is the nth term of the Geometric Progression 7, 21, 63, …, find:

(a) the value of n.

(b) hence, the sum of the n terms of the G.P.

Exam-ready answer 04 Mark

Answer

First term, a = 7

Common ratio, r = 21 ÷ 7 = 3

(a) The nth term of a G.P. is Tₙ = arⁿ⁻¹.

⇒ 1701 = 7 × 3ⁿ⁻¹

⇒ 3ⁿ⁻¹ = 1701 ÷ 7

⇒ 3ⁿ⁻¹ = 243

⇒ 3ⁿ⁻¹ = 3⁵

⇒ n − 1 = 5

⇒ n = 6

(b) Sum of n terms of a G.P. = \mathrm{S}_{\mathrm{n}}=\frac{\mathrm{a}(\mathrm{r}^{\mathrm{n}}-1)}{\mathrm{r}-1}

\mathrm{S}_6=\frac{7(3^6-1)}{3-1}

= \frac{7(729-1)}{2}

= \frac{7\times728}{2}

= 7 × 364

= 2548

Therefore, n = 6 and the sum of the first six terms is 2548.

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