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ICSEClass XMathematicsMatrices04 Mark2026 Hard

QQuestion

If A = \begin{bmatrix}3 & 1 \\ 5 & 3\end{bmatrix}, B = \begin{bmatrix}-1 & \mathrm{a} \\ 3 & -5\end{bmatrix} and AB = \begin{bmatrix}\mathrm{b} & 7 \\ 4 & 5\end{bmatrix}, find the values of a and b.

Exam-ready answer • 04 Mark

Answer

Given:

A = \begin{bmatrix}3 & 1 \\ 5 & 3\end{bmatrix} and B = \begin{bmatrix}-1 & \mathrm{a} \\ 3 & -5\end{bmatrix}

AB = \begin{bmatrix}3(-1)+1(3) & 3\mathrm{a}+1(-5) \\ 5(-1)+3(3) & 5\mathrm{a}+3(-5)\end{bmatrix}

⇒ AB = \begin{bmatrix}0 & 3\mathrm{a}-5 \\ 4 & 5\mathrm{a}-15\end{bmatrix}

But AB = \begin{bmatrix}\mathrm{b} & 7 \\ 4 & 5\end{bmatrix}

⇒ \begin{bmatrix}0 & 3\mathrm{a}-5 \\ 4 & 5\mathrm{a}-15\end{bmatrix} = \begin{bmatrix}\mathrm{b} & 7 \\ 4 & 5\end{bmatrix}

Comparing corresponding elements,

b = 0

and 3a − 5 = 7

⇒ 3a = 12

⇒ a = 4

Verification using the bottom-right element:

5a − 15 = 5

⇒ 5(4) − 15 = 5

⇒ 20 − 15 = 5

Therefore, a = 4 and b = 0.

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