QQuestion
In the given diagram, O is the centre of the circle and the tangent DE touches the circle at B. If ∠ADB = 32°. Find the values of x and y.

In the given diagram, O is the centre of the circle and the tangent DE touches the circle at B. If ∠ADB = 32°. Find the values of x and y.

Since AB is a diameter, the angle in a semicircle is a right angle.
Therefore, ∠ACB = 90°.
By the tangent-chord theorem:
∠DBC = ∠BAC = x
and ∠ABE = ∠BCA = y
Angles on the straight line DBE give:
x + 90° + y = 180°
⇒ x + y = 90° …(1)
In triangle ADB:
∠ADB + ∠DAB + ∠ABD = 180°
⇒ 32° + x + (x + 90°) = 180°
⇒ 2x + 122° = 180°
⇒ 2x = 58°
⇒ x = 29°
Substituting x = 29° in (1):
29° + y = 90°
⇒ y = 61°
Therefore, x = 29° and y = 61°.
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