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ICSEClass XMathematicsCircles04 Mark2026 Moderate

QQuestion

In the given diagram, O is the centre of the circle and the tangent DE touches the circle at B. If ∠ADB = 32°. Find the values of x and y.

In the given diagram, O is the centre of the circle and the tangent DE touches the circle at B

Exam-ready answer • 04 Mark

Answer

Since AB is a diameter, the angle in a semicircle is a right angle.

Therefore, ∠ACB = 90°.

By the tangent-chord theorem:

∠DBC = ∠BAC = x

and ∠ABE = ∠BCA = y

Angles on the straight line DBE give:

x + 90° + y = 180°

⇒ x + y = 90° …(1)

In triangle ADB:

∠ADB + ∠DAB + ∠ABD = 180°

⇒ 32° + x + (x + 90°) = 180°

⇒ 2x + 122° = 180°

⇒ 2x = 58°

⇒ x = 29°

Substituting x = 29° in (1):

29° + y = 90°

⇒ y = 61°

Therefore, x = 29° and y = 61°.

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