The cumulative-frequency table for the given continuous distribution is:
| Weight (in kg) |
Number of students |
Cumulative frequency |
| 35–40 |
4 |
4 |
| 40–45 |
6 |
10 |
| 45–50 |
10 |
20 |
| 50–55 |
24 |
44 |
| 55–60 |
26 |
70 |
| 60–65 |
17 |
87 |
| 65–70 |
8 |
95 |
| 70–75 |
5 |
100 |

(a) Total number of students, N = 100
Median position = \frac{\mathrm{N}}{2} = \frac{100}{2} = 50
From the ogive, the median weight is approximately 56 kg.
(b) Cumulative frequency at 60 kg = 70
Number of students weighing 60 kg or more = 100 − 70 = 30
Percentage = \frac{30}{100}\times100 = 30%
Therefore, 30% of the students weigh 60 kg or more.
(c) Number of students above the required weight = 20% of 100 = 20
Therefore, the cumulative frequency below the required weight = 100 − 20 = 80.
From the ogive, the weight corresponding to cumulative frequency 80 is approximately 63 kg.
Therefore, the weight above which 20% of the students lie is approximately 63 kg.