QQuestion
The following table gives the marks scored by a set of students in an examination. Calculate the mean of the distribution using the shortcut method.
| Marks | Number of students (f) |
|---|---|
| 0–10 | 3 |
| 10–20 | 8 |
| 20–30 | 14 |
| 30–40 | 9 |
| 40–50 | 4 |
| 50–60 | 2 |
The following table gives the marks scored by a set of students in an examination. Calculate the mean of the distribution using the shortcut method.
| Marks | Number of students (f) |
|---|---|
| 0–10 | 3 |
| 10–20 | 8 |
| 20–30 | 14 |
| 30–40 | 9 |
| 40–50 | 4 |
| 50–60 | 2 |
Take the assumed mean A = 25.
| Marks | f | x | d = x − A | fd |
|---|---|---|---|---|
| 0–10 | 3 | 5 | −20 | −60 |
| 10–20 | 8 | 15 | −10 | −80 |
| 20–30 | 14 | 25 | 0 | 0 |
| 30–40 | 9 | 35 | 10 | 90 |
| 40–50 | 4 | 45 | 20 | 80 |
| 50–60 | 2 | 55 | 30 | 60 |
⇒ Σf = 40 and Σfd = 90
⇒ Mean = A + \frac{Σfd}{Σf}
⇒ Mean = 25 + \frac{90}{40}
⇒ Mean = 25 + 2.25
Therefore, the mean is 27.25.
More ICSE Easy level questions
The following distribution gives the daily wages of 60 workers of a factory: Daily income (₹) Number of workers 200–300 6 300–400 10 400–500 14 500–600 16 600–700 10 700–800 4 Use graph paper. Take 2 cm = ₹100 along one axis and 2 cm = 2 workers along the other axis. Draw a histogram and hence find the mode of the distribution.
Use graph paper to answer this question. During a medical check-up of 60 students in a school, their weights were recorded as follows: Weight (kg) Number of students 28–30 2 30–32 4 32–34 10 34–36 13 36–38 15 38–40 9 40–42 5 42–44 2 Taking 2 cm = 2 kg along one axis and 2 cm = 10 students along the other axis, draw an ogive. Use the graph to find: (a) the median (b) the upper quartile (c) the number of students whose weight is above 37 kg.
Which of the following cannot be determined graphically for a grouped frequency distribution? (a) Median (b) Mode (c) Quartiles (d) Mean
Find the mean of the following frequency distribution using step-deviation method. Take assumed mean = 28. Class interval Frequency 0–8 10 8–16 20 16–24 14 24–32 16 32–40 18 40–48 22
Rakhi’s mobile number has the following integers : 1, 6, 9, 8, 9, 1, 7, 8, 9 The mode of the above given data is : (a) 1 (b) 6 (c) 8 (d) 9
The following observations are arranged in ascending order: 27, 31, 46, 52, x, x + 4, 71, 79, 85, 90 If the median is 64, then the value of x is: (a) 60 (b) 61 (c) 62 (d) 66
Using a graph paper, draw an ogive for the following distribution which shows a record of weight in kilograms of 100 students. Weight (in kg) Number of students 35–40 4 40–45 6 45–50 10 50–55 24 55–60 26 60–65 17 65–70 8 70–75 5 Use your ogive to estimate the following: (a) the median weight of the students. (b) percentage of students whose weight is 60 kg or more. (c) the weight above which 20% of the students lie.
Assertion (A): The mean of the first 9 natural numbers is 4.5. Reason (R): Mean = (a) A is true, R is false. (b) A is false, R is true. (c) Both A and R are true, and R is the correct reason for A. (d) Both A and R are true, and R is not the correct reason for A.
The histogram drawn on the graph represents the number of students of different heights (in cm). Using the graph, answer the following: (a) the number of students whose height is 150 cm and above. (b) the modal height. (c) the total number of students.
For the following frequency distribution, find: (a) the mean, to the nearest whole number. (b) the median. x 10 11 12 13 14 15 16 f 3 2 2 6 3 5 3
The following table gives the duration of movies in minutes: Duration (minutes) Number of movies 100–110 5 110–120 10 120–130 17 130–140 8 140–150 6 150–160 4 Using the step-deviation method, find the mean duration of the movies.
A life insurance agent found the following distribution of ages of 100 policy holders: Age (years) Frequency Cumulative frequency 20–25 2 2 25–30 4 6 30–35 12 18 35–40 20 38 40–45 28 66 45–50 22 88 50–55 8 96 55–60 4 100 On a graph sheet, draw an ogive using the given data. Take 2 cm = 5 years along one axis and 2 cm = 10 policy holders along the other axis. Use your graph to find: (a) the median age. (b) the number of policy holders whose age is above 52 years.