Madhyamik Class 10 Physical Science Question Paper Solved 2022
Physical Science
Time – Three Hours Fifteen Minutes
(First fifteen minutes for reading the Question paper only)
Full Marks – 90
(For Regular and Sightless Regular Candidates)
Full Marks – 100
(For External and sightless External Candidates)
Special credits will be given for answers which are brief and to the point.
Marks will be deducted for spelling mistakes, untidiness and bad handwriting
Figures in the margin indicate full marks for each Question.
Only the External Candidates will answer Group -E
Figures in the margin indicate full marks for each Question.
Group – A
1. Multiple choice Questions. Four alternative answers are given for each of the following Questions. Write the correct one. [1×15=15]
Question 1.1.
Which layer of atmosphere has the greatest density?
- Troposphere
- Stratosphere
- Mesosphere
- Thermosphere
Solution
a. Troposphere
Explanation: The troposphere is the lowest layer of Earth’s atmosphere and contains approximately 75% of the atmosphere’s mass, making it the densest layer.
Question 1.2.
The P – V graph of Boyle’s Law related to gas is
Solution
(b)
Explanation:
The P-V graph (Pressure vs. Volume) related to Boyle’s Law is a curve that shows an inverse relationship between pressure (P) and volume (V) of a gas at constant temperature.
Question 1.3.
The relation between molecular mass (M) and vapour density (D) of gaseous substance is
- 2M=D
- M=D2
- M=2.8D
- M=2D
Solution
d. M = 2D
Explanation: Molecular mass is twice the vapour density of a substance.
Question 1.4.
If the radius of curvature of a concave mirror is 20 cm, then focal length of the mirror will be
- 20 cm
- 15 cm
- 10 cm
- 40 cm
Solution
c. 10 cm
Explanation: The focal length (f) of a concave mirror is half of its radius of curvature (R).
So, f = 20\over2 = 10 cm
Question 1.5.
The wavelength of which of the following is greater than that of visible light?
- x-ray
- infrared ray
- γ – ray
- ultraviolet ray
Solution
b. Infrared ray
Explanation: Infrared rays have a longer wavelength than visible light, while X-rays, gamma (γ) rays and ultraviolet rays have shorter wavelengths than visible light.
Question 1.6.
Dentists use
- convex mirror
- convex lens
- concave mirror
- concave lens
Solution
c. Concave mirror
Explanation: Dentists use concave mirrors because they produce a magnified and upright image of the teeth, which helps in detailed examination.
Question 1.7.
The charge of an electron is
- -3.2 × 10-19C
- -1.6 × 10-19C
- 6 × 10-19 C
- 3.2 × 10-19 C
Solution
b. -1.6 × 10⁻¹⁹ C
Explanation: The charge of an electron is negative and its magnitude is 1.6 × 10⁻¹⁹ coulombs.
Question 1.8.
If the resistance (R) of the conductor and time of flow of current in the conductor (t) remain unchanged, the relation between the heat produced (H) the conductor and flow of current (l) is
- H ∝ I
- H ∝ {1\over I^2}
- H ∝ I2
- H ∝ {1\over I}
Solution
c. H ∝ I²
Explanation: According to Joule’s law of heating, the heat produced in a conductor is given by:
H = I2Rt
Question 1.9.
If 12 C of charge flows through a conductor for 2 minutes, the electric current is
- 6 amperes
- 0.1 amperes
- 24 amperes
- 10 amperes
Solution
b. 0.1 amperes
Explanation:
Q = 12 C (charge)
t = 2 min = 2 × 60 = 120 seconds
Current (I) is calculated using the formula:
I = 12/120 = 0.1 A
So, the electric current is 0.1 amperes.
Question 1.10.
Number of groups in the long periodic table is
- 9
- 13
- 18
- 19
Solution
c. 18
Explanation: The long periodic table has 18 groups (columns) that categorize elements based on their similar chemical properties.
Question 1.11.
The order of oxidising properties of Cl (17), I(53), F(9), Br(35) belonging to group 17 of long periodic table is
- F < Cl < Br < I
- Cl > I > F > Br
- Cl > F > Br > I
- F > Cl > Br > I
Solution
d. F > Cl > Br > I
Explanation: In Group 17 (halogens), the oxidizing power decreases down the group. Fluorine (F) is the strongest oxidizing agent, followed by chlorine (Cl), bromine (Br), and iodine (I).
Question 1.12.
For which of the following ionic compounds no ion has octet?
- LiH
- CaO
- NaCl
- MgCl2
Solution
a. LiH
Explanation: In lithium hydride (LiH), lithium (Li) has only 2 electrons in its outer shell after bonding (duplet), and hydrogen (H) also has 2 electrons (which is a complete shell for it). Thus, neither ion achieves an octet configuration. In the other compounds, the ions achieve an octet configuration.
Question 1.13.
The solid state of which of the following compounds is not composed of molecules?
- Sugar
- Glucose
- Sodium fluoride
- Hydrogen chloride
Solution
c. Sodium fluoride
Explanation: Sodium fluoride (NaF) is an ionic compound, meaning it exists as a lattice of ions rather than discrete molecules. In contrast, sugar, glucose, and hydrogen chloride can form molecular structures.
Question 1.14.
Acetic acid is a weak electrolyte because in an aqueous solution acetic acid is
- non-conductor of electricity
- completely dissociated
- partially dissociated
- not dissociated
Solution
c. Partially dissociated
Explanation: Acetic acid (CH₃COOH) is a weak electrolyte because it does not completely dissociate in aqueous solution; instead, it partially ionizes into acetate ions (CH₃COO⁻) and hydrogen ions (H⁺).
Question 1.15.
During electrolysis
- oxidation occurs at the cathode and reduction occurs at the anode
- oxidation occurs at both the electrodes
- reduction occurs at both the electrodes
- reduction occurs at the cathode and oxidation occurs at the anode.
Solution
d. Reduction occurs at the cathode and oxidation occurs at the anode.
Explanation: During electrolysis, reduction (gain of electrons) takes place at the cathode, while oxidation (loss of electrons) occurs at the anode.
Group – B
2. Answer the following Questions (alternatives are to be noted):
Question 2.1.
Mention one fuel which is alternative to fossil fuel. [1]
Solution
One alternative fuel to fossil fuels is biofuel.
Question 2.2.
Write the name of a gas which increases atmospheric temperature. [1]
OR
Fill in the blank : [1]
__ radiation, coming from the sun is prevented by the ozone layer from falling on the earth’s surface.
Solution
A gas that increases atmospheric temperature is carbon dioxide (CO2)
OR
Ultraviolet (UV) radiation, coming from the sun, is prevented by the ozone layer from falling on the earth’s surface.
Question 2.3.
What is SI unit of pressure of gas? [1]
Solution
The SI unit of pressure of a gas is the pascal (Pa).
Question 2.4.
What are constants in Charles’ law? [1]
OR
Write whether the following statement is True or False: [1]
Per degree interval in kelvin scale of temperature is equal to per degree interval in celcius scale.
Solution
In Charles’ law, the constants are pressure and the mass of gas.
OR
True: Per degree interval in the Kelvin scale is equal to per degree interval in the Celsius scale.
Question 2.5.
Is it possible to form a virtual image of shorter length than the length of the object by any mirror? [1]
Solution
Yes, it is possible to form a virtual image of a shorter length than the length of the object using a concave mirror.
Question 2.6.
Which type of mirror is used in the headlight of a motor car? [1]
Solution
A concave mirror is used in the headlight of a motor car.
Question 2.7.
If the refractive indices of a medium for red and blue colours of light are μr and μb respectively, which one is greater in magnitude? [1]
Solution
μr < μb
Question 2.8.
What is the SI unit of electric charge? [1]
Solution
The SI unit of electric charge is the coulomb (C).
Question 2.9.
What is the unit of electrical conductance? [1]
OR
What are the constituents of fuse wire? [1]
Solution
The unit of electrical conductance is the Siemens (S).
OR
Fuse wire is made of an alloy of tin (Sn) and lead (Pb). The alloy is usually made up of 62% tin and 38% lead.
Question 2.10.
‘Kilowatt-hour’ is the unit of which physical quantity? [1]
Solution
‘Kilowatt-hour’ is the unit of energy.
Question 2.11.
Match the Right column with the Left column : [1 × 4 = 4]
Left Column | Right Column |
2.11.1 Acetic acid
2.11.2 Glass 2.11.3 Most electro-negative element 2.11.4 One Noble Element |
(a) non-conductor of electricity
(b) Weak electrolyte (c) Krypton (d) Fluorine |
Solution
2.11.1 Acetic acid → (b) Weak electrolyte
2.11.2 Glass → (a) non-conductor of electricity
2.11.3 Most electro-negative element → (d) Fluorine
2.11.4 One noble element → (c) Krypton
Question 2.12.
Arrange F, I, Br, CI in decreasing order of electronegativity [1]
Solution
F > Cl > Br > I
Question 2.13.
In which group of the long periodic table, elements of all three physical states – gaseous, liquid and solid are present? [1]
OR
To which group of the long periodic table do the alkali metals belong? [1]
Solution
Group 17 (Halogens) of the long periodic table contains elements in all three physical states: gaseous (e.g., F, Cl), liquid (e.g., Br), and solid (e.g., I).
OR
The alkali metals belong to Group 1 of the long periodic table.
Question 2.14.
Show the conventional representation of the H2O molecule by ‘dash’ sign. [1]
Solution
The conventional representation of an H2O molecule using ‘dash’ signs is
H – O – H
Question 2.15.
The electronic configuration of a hydride ion (H–) is like the electronic configuration of the atom of which element? [1]
OR
Draw the Lewis dot diagram of H2 molecule. [1]
Solution
The hydride ion (H⁻) has gained an extra electron, giving it an electronic configuration similar to that of helium (He), which is 2.
OR
The Lewis dot diagram for the H2 molecule is represented as follows:
H : H
Question 2.16.
Give an example of a covalent liquid. [1]
Solution
An example of a covalent liquid is water (H2O).
Question 2.17.
Write whether the following statement is True or False : [1]
The electrical conductivity of solid NaCl is greater than the electrical conductivity of fused NaCl.
Solution
False.
Correction: The electrical conductivity of fused NaCl is greater than that of solid NaCl because, in the solid state, NaCl does not have free ions to conduct electricity.
Question 2.18.
What reaction occurs at the cathode in the electrolyte method of extraction of aluminium? [1]
OR
Write whether the following statement is True or False: [1]
Free electrons carry electricity through electrolytic substances.
Solution
At the cathode in the electrolyte method of aluminium extraction, aluminium ions (Al³⁺) are reduced to form aluminium metal (Al). The reaction is:
Al3+ +3e− →Al
OR
False. Free ions, not free electrons, carry electricity through electrolytic substances.
Group – C
3. Answer the following Questions (alternatives are to be noted): [2 × 9 = 18]
Question 3.1.
What is global warming? [2]
Solution
Global warming is the gradual increase in Earth’s average surface temperature due to the buildup of greenhouse gases, such as carbon dioxide (CO2) and methane (CH4), in the atmosphere. These gases trap heat from the sun, causing a rise in temperature, which leads to climate changes like melting ice caps, rising sea levels, and more extreme weather patterns.
Question 3.2
At a pressure of 770 mm Hg, a fixed mass of hydrogen gas occupies a volume of 75cm at 27°C. What volume will the mass of hydrogen gas occupy at that temperature and 750 mmHg pressure? [2]
OR
What will be the volume of 64 g of O2 gas (O=16) at a pressure of 2 atmospheres and temperature of 300K? [2]
(R = 0.082 litre – atmosphere mol-1K-1)
Solution
Initial pressure (P1) = 770 mm Hg
Initial volume (V1) = 75 cm3
Final pressure (P2) = 750 mm Hg
Final volume (V2) =?
Apply Boyle’s Law:
P1V1 = P2V2
Or, V2 = P_1V_1\over P_2
or, V2 = 770 × 75\over 750 = 77 cm3
The volume of hydrogen gas at 750 mm Hg pressure will be 77 cm3.
OR
Mass of O2 = 64 g
Pressure (P) = 2 atm
Temperature (T) = 300 K
R = 0.082 L·atm·mol⁻¹·K⁻¹
Molar mass of O₂ (O = 16) = 32 g
mole (n) = mass\ of\ O_2\over molar\ mass\ of\ O_2 = 2
The ideal gas law is: PV = nRT
V = nRT\over P
V = 2 × 0.082 × 300\over 2
V = 2 × 0.082 × 300\over 2 = 24.6
The volume of 64 g of O₂ gas at 2 atm and 300 K is 24.6 litres.
Question 3.3.
Determine the angle of deviation for the refraction of light rays from rarer to denser medium. [2]
(angle of incidence = i, angle of refraction = r)
OR
Why do the green leaves of trees appear ‘green’ in sunlight? [2]
Solution
The angle of deviation (δ) for light rays passing from a rarer to a denser medium is given by:
δ = i−r
Where:
- i is the angle of incidence,
- r is the angle of refraction.
OR
Green leaves appear green because they contain a pigment called chlorophyll, which absorbs most of the blue and red wavelengths of light and reflects the green wavelength. Since green light is reflected, it is the colour we see.
Question 3.4.
Give the definition of electromotive force of an electric cell in open circuit. [2]
Solution
The electromotive force (emf) of an electric cell in an open circuit is the maximum potential difference between the two terminals of the cell when no current is flowing through the circuit. It represents the total energy provided by the cell per unit charge to move it through the circuit.
Question 3.5.
Why are the elements of group 2 of the long periodic table called alkaline earth metals? [2]
OR
Give example of a transitional element and a transuranic element. [2]
Solution
The elements of Group 2 in the long periodic table are called alkaline earth metals because:
- Their oxides and hydroxides are alkaline (basic) in nature, meaning they can neutralize acids.
- These metals are found in the earth’s crust as compounds, hence the term “earth” metals.
OR
An example of a transitional element is iron (Fe), and an example of a transuranic element is plutonium (Pu).
Question 3.6.
What type of chemical bond is present in NH3? Draw Lewis electron dot diagram of NH3. [2]
(The atomic number of H and N are 1 and 7 respectively)
Solution
Ammonia (NH3) has covalent bonds.
Lewis electron dot diagram of NH3 :
Question 3.7.
How is ionic bond formed in sodium fluoride? (The atomic number of F and Na are 9 and 11 respectively). [2]
OR
C has 4 electrons in its outermost shell and O has 6 electrons in its outermost shell. Draw the Lewis dot diagram of CO2 molecule. [2]
Solution
In sodium fluoride (NaF), an ionic bond forms through the transfer of electrons:
- Sodium (Na) loses one electron (2, 8, 1 → 2, 8) to become Na+.
- Fluorine (F) gains one electron (2, 7 → 2, 8) to become F–.
The electrostatic attraction between Na⁺ and F⁻ creates the ionic bond in NaF.
OR
Lewis dot diagram of CO2 molecule:
Question 3.8.
Distinguish between naphthalene and sodium chloride by two physical properties. [2]
Solution
Properties | Sodium chloride | Naphthalene |
Melting Point | Has a high melting point (around 801°C). | Has a low melting point (around 80°C) |
Solubility | Highly soluble in water | Insoluble in water |
Question 3.9.
What is meant by strong electrolyte? [2]
OR
What are meant by cathode and anode electrodes? [2]
Solution
Strong Electrolyte
A strong electrolyte is a substance that completely dissociates into ions when dissolved in water. This means that it conducts electricity very well due to the high concentration of free-moving ions in solution.
Examples of strong electrolytes include sodium chloride (NaCl) and potassium nitrate (KNO3).
Cathode and Anode Electrodes
- Cathode: The cathode is the electrode where reduction occurs during electrochemical reactions. It is negatively charged in electrolysis, attracting cations (positively charged ions).
- Anode: The anode is the electrode where oxidation occurs. It is positively charged in electrolysis, attracting anions (negatively charged ions).
Group – D
4. Answer the following Questions (alternatives are to be noted):
Question 4.1.
Establish the combined form of Boyle’s law and Charles’ law. [3]
Solution
Let V be the volume of a given mass of gas at pressure P and temperature T (absolute),
From Boyle’s law: V ∝ 1/P (m and T constant)
From Charle’s law: V ∝ T (m and P constant)
By combining two laws we have,
V ∝ T/P or,
V = K T/P (Where K = proportionality constant)
or, PV = KT
or, PV = nRT
Where n is the number of moles of gas, R is the universal gas constant (0.08206 L·atm/mol·K)
Question 4.2.
By the reaction of aluminium with 40 grams of metallic oxide and high temperature, 28 grams of the metal and 25.5 grams of aluminium oxide are produced. How many grams of aluminium are required for the reaction?
OR
The chemical equation for the reaction between sulphuric acid and sodium hydroxide is:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
How many grams of sodium hydroxide will be required to react completely with 4.9 grams of sulphuric acid?
(H=1, O=16, Na=23, S=32). [3]
Solution
Given
- Mass of metallic oxide = 40 grams
- Mass of metal produced = 28 grams
- Mass of aluminum oxide produced = 25.5 grams
Let’s assume the mass of aluminum required for the reaction is xxx grams.
According to the law of conservation of mass:
Mass of reactants = Mass of products
⇒ 40 + x = 28 + 25.5
⇒ x = 53.5- 40 = 13.5 g
∴ 13.5 grams of aluminum are required for the reaction.
OR
Molar mass of H2SO4 = 2 + 32 + 4×16 = 98 g
Molar mass of NaOH = 23 + 16 + 1 = 40 g
From the balanced chemical equation:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
98 g 80 g
Amount of NaOH required to completely react with 98 g H2SO4 = 80 g
∴ Amount of NaOH required to completely react with 4.9 g H2SO4 = 80\over 98 × 4.9 = 4.0 g
Question 4.3.
A light is incident from air medium on another medium. If the refractive index of this medium is 1.5 and the wavelength of light in this medium is 4000 Å what is the wavelength of light in the air medium ? What is the velocity of the light in this medium? [3]
OR
As a result of refraction of light through an equilateral prism the angle of deviation becomes 40°. If the path of the ray through the prism is parallel to the base of the prism, determine the angle of incidence at the first surface of prism. [3]
Solution
Finding the wavelength:
μ = 1.5
λmedium = 4000 Å
λair = μ × λmedium
⇒ λair = 1.5 × 4000 = 6000 Å
Find the velocity:
μ = 1.5
vair = 3 × 108 m/s
vmedium = 3 × 108/1.5 = 2 × 108 m/s
OR
Angle of deviation (δ) = 40º
Angle of prism (A) = 60º
We know, δ = 2i−A
⇒ i = δ + A\over 2
⇒ i = 40º + 60º\over 2 = 50º
The angle of incidence at the first surface of the prism is 50°.
Question 4.4.
Draw refracted rays for the incident rays which are parallel to the principal axis of a convex lens. Mark focus (F). [3]
OR
Explain the converging action of a convex lens. [3]
Solution
Ray Diagram for convex lens:
OR
Converging action of the convex lens as a combination of prisms:
A lens is made up of a set of prisms, the prisms in the upper part of a convex lens have their bases downwards, while the prisms in the lower part of the lens have their bases upwards. When a beam of parallel rays of light incident on a convex lens, the prisms in the upper part of the lens bend the incident rays downward and the prisms in the lower part of the lens bend the incident rays upwards. The central part which is a parallel sided glass block passes the incident ray undeviated. Thus the convex lens converges the parallel beam of light to a point called principal focus (F) of the lens and hence a convex lens is called a converging lens.
Question 4.5.
What is long-sightedness? What type of lens is used to remedy this defect? [2+1]
Solution
Long-sightedness, also known as hypermetropia, is a vision defect in which a person can see distant objects clearly but has difficulty focusing on nearby objects. This happens because the image of close objects is formed behind the retina instead of directly on it, often due to a shorter-than-normal eyeball or a less curved cornea.
To correct long-sightedness, a convex lens is used.
Question 4.6.
If two electric bulbs of ratings ‘240V-60 W’ and ‘240V-100W’ are connected in series, which one will shine brighter? (Filaments of both the bulbs are of the same material).[3]
OR
An electric cell of internal resistance 5 Ω and emf 2 V is connected to a resistor of 15 Ω. Determine the potential difference between the two ends of the cell. [3]
Solution
For bulbs of the same voltage rating, the bulb with a higher wattage (power) has a lower resistance. Since both bulbs are in series and the current is the same, the bulb with higher resistance (i.e., the 60W bulb) will drop a larger voltage across it and consume more power than it would when connected to a 240V supply directly.
Thus, the 60W bulb will shine brighter than the 100W bulb in this series connection.
OR
EMF = electromotive force of the cell = 2 V
r = internal resistance of the cell = 5 Ω
R = external resistor = 15 Ω
RTotal = R + r = 15 + 5 = 20 Ω
Current (I) = 2\over 20 = 0.1 A
V = EMF − I⋅r = 2V – (0.1 A × 5 Ω) = 1.5 V
Thus, the potential difference between the two ends of the cell is 1.5 V.
Question 4.7.
Which energy is transformed to which energy in an electric motor? Why in domestic circuits, electric bulbs, electric fans, refrigerators etc., are connected in parallel combination ? [3]
Solution
In an electric motor, electrical energy is transformed into mechanical energy.
Domestic Circuits Use Parallel Combination because
- Each appliance gets the same voltage, ensuring it works properly.
- If one appliance fails, others still work. This prevents disruptions.
- Each appliance has its own switch allowing for easy operation of each appliance.
Question 4.8.
State Ohm’s law. If a potential difference of 10 V is applied between the two ends of a conductor, an electric current of 0.1 A flows. Determine the resistance of the conductor. [2+1]
Solution
Ohm’s Law states that the current (I) flowing through a conductor is directly proportional to the voltage (V) across it, provided the temperature remains constant.
Mathematically, it is expressed as: V = I × R
Given Data
- Potential Difference (V) = 10 V
- Current (I) = 0.1 A
R = V\over I = 10\over 0.1 = 100 Ω
Question 4.9.
The first three elements of group 16 of long periodic table are O, S, and Se. Arrange them in the order of decreasing atomic radius, increasing electro-negativity and decreasing ionization energy. [1 + 1 + 1]
Solution
Atomic Radius: Se > S > O
Electronegativity: O < S < Se
Ionization Energy: Se < S < O
Question 4.10.
What type of chemical bond is present in MgCl2? How are the chemical bonds formed in MgCl2? (Atomic number of Mg and Cl are 12 and 17 respectively). [1+2]
OR
Explain why an aqueous solution of sodium chloride is the conductor of electricity but the aqueous solution of sugar or glucose is not. [3]
Solution
MgCl2 (magnesium chloride) contains ionic bonds.
Formation of Chemical Bonds in MgCl2
- Magnesium tends to lose its two valence electrons to achieve a stable electron configuration, forming a Mg2+ ion.
- Each chlorine atom can gain one electron to complete its octet, forming two Cl– ions.
- The Mg2+ ion and the two Cl– ions attract each other due to opposite charges, resulting in the formation of MgCl2 through ionic bonding.
OR
An aqueous solution of sodium chloride (NaCl) conducts electricity because NaCl is an ionic compound. When dissolved in water, it dissociates into free-moving Na⁺ and Cl⁻ ions, which carry electric charge and enable the flow of current.
Whereas, sugar or glucose are covalent compounds that do not dissociate into ions when dissolved in water. Since there are no free-moving charged particles in the solution, it cannot conduct electricity.
Question 4.11.
What is electroplating? What is the cathode in the electroplating of silver over a copper material? [2+1]
Solution
Electroplating is a process that uses electric current to deposit a layer of metal onto a surface. This technique is often used to enhance the appearance, corrosion resistance, and conductivity of the material being plated.
In the electroplating of silver over copper, the copper object being coated serves as the cathode.
Question 4.12.
Write the reaction occurring at the cathode in the electrolysis of acidulated water using platinum electrodes. Why is acidulated water instead of pure water used for electrolysis? [1+2]
OR
Write the reactions occurring at cathode and anode in the electrolysis of the aqueous solution of CuSO4 using Cu – electrodes. What is used as anode in refining of impure copper metal by the process of electrolysis? [2+1]
Solution
In the electrolysis of acidulated water, the reaction occurring at the cathode (where reduction takes place) is:
2H+ + 2e−→ H2↑
Acidulated Water is Used
- Increased Conductivity: Acidulated water has more ions, improving conductivity compared to pure water.
- Faster Reaction: The presence of H+ ions accelerates hydrogen gas formation at the cathode, making electrolysis more efficient.
OR
Reactions in Electrolysis of CuSO4 with Cu Electrodes
At the Cathode: Cu2+ + 2e − → Cu (s)
At the Anode: Cu (s) → Cu2+ + 2e−
In the refining of impure copper, the anode used is made of impure copper metal.
Group – E
(For external candidates only)
5. Answer the following Questions (any four) [1×4 = 4]
Question 5.1.
What is the SI unit of calorific value of fuels?
Solution
The SI unit of calorific value of fuels is joules per kilogram (J/kg).
Question 5.2.
Write down the ideal gas equation for 1 mol gas.
Solution
PV=RT (where, n = 1)
Question 5.3.
From which group to group 12 of the long periodic table are the transitional elements located?
Solution
The transitional elements are located from Group 3 to Group 12 of the long periodic table.
Question 5.4.
Which type of energy is transformed to electrical energy in a dynamo?
Solution
In a dynamo, mechanical energy is transformed into electrical energy.
Question 5.5.
How many covalent bonds are present in CHCl3 molecules?
Solution
In a CHCl3 (chloroform) molecule, there are four covalent bonds.
6. Answer the following Questions (any three) : [2 x 3 = 6]
Question 6.1.
If two conductor wires of resistances 6 ohms and 4 ohms are connected in parallel combination, what will be the equivalent resistance of the combination?
Solution
For parallel Combination: {1\over R_{eq}} = {1\over R_1} + {1\over R_2}
or, {1\over R_{eq}} = {1\over 6} + {1\over 4}
or, {1\over R_{eq}} = {2 + 3\over 12}
or, Req = 2.4 Ω
Question 6.2.
What is meant by the principal axis of a concave lens?
Solution
The principal axis of a concave lens is an imaginary straight line that runs horizontally through the center of the lens. It helps measure angles of light as they pass through the lens.
Question 6.3.
Mention similarity of properties of hydrogen with two properties of group 17 elements of long periodic table.
Solution
Hydrogen shares similarities with group 17 elements (halogens) in the following ways:
- Both hydrogen and halogens have valency one.
- Both hydrogen and halogens exist as diatomic molecules in their gaseous states.
Question 6.4.
Why fused sodium chloride can conduct electricity?
Solution
Fused sodium chloride can conduct electricity because, when it is melted (fused), the ionic bonds holding the Na⁺ and Cl⁻ ions in a rigid structure are broken. This allows the ions to move freely in the molten state. The movement of these charged ions enables the conduction of electric current.
——-End——