As we know, from the equation of motion,
v = u + at
Given,
Acceleration (a) = 2 m s -2
Initial velocity (u) = 0
time (t) = 5 s
Substituting the values in the formula, we get,
v = 0 + 2 × 5 = 10 ms-1
Hence, the velocity acquired = 10 m s-1
(ii) According to the equation of motion
S = ut + 1/2 at2
= 0 × 5 + 1/2 × 2 × 52
= 1/2 × 2 × 52
= 25 m
Hence, distance travelled = 25 m